Base | Representation |
---|---|
bin | 111101001001111100… |
… | …1011011101010000111 |
3 | 110112222122011202121211 |
4 | 1322103321123222013 |
5 | 4122431030401002 |
6 | 140155440352251 |
7 | 12326326226161 |
oct | 1722371335207 |
9 | 415878152554 |
10 | 131330325127 |
11 | 507735aa091 |
12 | 21552315687 |
13 | c4cc699771 |
14 | 64dc041931 |
15 | 3639a43dd7 |
hex | 1e93e5ba87 |
131330325127 has 2 divisors, whose sum is σ = 131330325128. Its totient is φ = 131330325126.
The previous prime is 131330325083. The next prime is 131330325253. The reversal of 131330325127 is 721523033131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131330325127 - 235 = 96970586759 is a prime.
It is a super-2 number, since 2×1313303251272 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131330325727) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65665162563 + 65665162564.
It is an arithmetic number, because the mean of its divisors is an integer number (65665162564).
Almost surely, 2131330325127 is an apocalyptic number.
131330325127 is a deficient number, since it is larger than the sum of its proper divisors (1).
131330325127 is an equidigital number, since it uses as much as digits as its factorization.
131330325127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11340, while the sum is 31.
Adding to 131330325127 its reverse (721523033131), we get a palindrome (852853358258).
The spelling of 131330325127 in words is "one hundred thirty-one billion, three hundred thirty million, three hundred twenty-five thousand, one hundred twenty-seven".
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