Base | Representation |
---|---|
bin | 11101110111000110111111… |
… | …000011010001000101101101 |
3 | 122020000001202210112211102221 |
4 | 131313012333003101011231 |
5 | 114203204200100030402 |
6 | 1143152210122315341 |
7 | 36443211146612506 |
oct | 3567067703210555 |
9 | 566001683484387 |
10 | 131330420314477 |
11 | 38933a1154398a |
12 | 12890870058b51 |
13 | 5838536b495b7 |
14 | 24605d7923bad |
15 | 102b313e70337 |
hex | 7771bf0d116d |
131330420314477 has 2 divisors, whose sum is σ = 131330420314478. Its totient is φ = 131330420314476.
The previous prime is 131330420314381. The next prime is 131330420314571. The reversal of 131330420314477 is 774413024033131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 67221157720201 + 64109262594276 = 8198851^2 + 8006826^2 .
It is a cyclic number.
It is not a de Polignac number, because 131330420314477 - 27 = 131330420314349 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131330420314777) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65665210157238 + 65665210157239.
It is an arithmetic number, because the mean of its divisors is an integer number (65665210157239).
Almost surely, 2131330420314477 is an apocalyptic number.
It is an amenable number.
131330420314477 is a deficient number, since it is larger than the sum of its proper divisors (1).
131330420314477 is an equidigital number, since it uses as much as digits as its factorization.
131330420314477 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 508032, while the sum is 43.
The spelling of 131330420314477 in words is "one hundred thirty-one trillion, three hundred thirty billion, four hundred twenty million, three hundred fourteen thousand, four hundred seventy-seven".
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