131330531225435 has 4 divisors (see below), whose sum is σ = 157596637470528. Its totient is φ = 105064424980344.

The previous prime is 131330531225269. The next prime is 131330531225447. The reversal of 131330531225435 is 534522135033131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131330531225435 - 2¹⁰ = 131330531224411 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131330531225392 and 131330531225401.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13133053122539 + ... + 13133053122548.

It is an arithmetic number, because the mean of its divisors is an integer number (39399159367632).

Almost surely, 2^{131330531225435} is an apocalyptic number.

131330531225435 is a deficient number, since it is larger than the sum of its proper divisors (26266106245093).

131330531225435 is an equidigital number, since it uses as much as digits as its factorization.

131330531225435 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26266106245092.

The product of its (nonzero) digits is 486000, while the sum is 41.

Adding to 131330531225435 its reverse (534522135033131), we get a palindrome (665852666258566).

The spelling of 131330531225435 in words is "one hundred thirty-one trillion, three hundred thirty billion, five hundred thirty-one million, two hundred twenty-five thousand, four hundred thirty-five".