Base | Representation |
---|---|
bin | 11101110111000111100001… |
… | …100111011100000110101111 |
3 | 122020000010021012202012012001 |
4 | 131313013201213130012233 |
5 | 114203211342024102002 |
6 | 1143152343435553131 |
7 | 36443231421006406 |
oct | 3567074147340657 |
9 | 566003235665161 |
10 | 131331000222127 |
11 | 38934189919102 |
12 | 128909b22bb7a7 |
13 | 58385ca02ba14 |
14 | 246065095a63d |
15 | 102b349d1ea87 |
hex | 7771e19dc1af |
131331000222127 has 2 divisors, whose sum is σ = 131331000222128. Its totient is φ = 131331000222126.
The previous prime is 131331000221989. The next prime is 131331000222173. The reversal of 131331000222127 is 721222000133131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131331000222127 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131331000222095 and 131331000222104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131331000229127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65665500111063 + 65665500111064.
It is an arithmetic number, because the mean of its divisors is an integer number (65665500111064).
Almost surely, 2131331000222127 is an apocalyptic number.
131331000222127 is a deficient number, since it is larger than the sum of its proper divisors (1).
131331000222127 is an equidigital number, since it uses as much as digits as its factorization.
131331000222127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 28.
Adding to 131331000222127 its reverse (721222000133131), we get a palindrome (852553000355258).
The spelling of 131331000222127 in words is "one hundred thirty-one trillion, three hundred thirty-one billion, two hundred twenty-two thousand, one hundred twenty-seven".
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