Base | Representation |
---|---|
bin | 1011111100011100100111… |
… | …1000101011011111100111 |
3 | 1201111111211110120220112121 |
4 | 2333013021320223133213 |
5 | 3210133043114240003 |
6 | 43533132552330411 |
7 | 2523556340661355 |
oct | 277071170533747 |
9 | 51444743526477 |
10 | 13133102102503 |
11 | 42037988373a9 |
12 | 15813493a3a07 |
13 | 7435a5442c56 |
14 | 3359074b47d5 |
15 | 17b94ea0bcbd |
hex | bf1c9e2b7e7 |
13133102102503 has 2 divisors, whose sum is σ = 13133102102504. Its totient is φ = 13133102102502.
The previous prime is 13133102102437. The next prime is 13133102102539. The reversal of 13133102102503 is 30520120133131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13133102102503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13133102102563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566551051251 + 6566551051252.
It is an arithmetic number, because the mean of its divisors is an integer number (6566551051252).
Almost surely, 213133102102503 is an apocalyptic number.
13133102102503 is a deficient number, since it is larger than the sum of its proper divisors (1).
13133102102503 is an equidigital number, since it uses as much as digits as its factorization.
13133102102503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 13133102102503 its reverse (30520120133131), we get a palindrome (43653222235634).
The spelling of 13133102102503 in words is "thirteen trillion, one hundred thirty-three billion, one hundred two million, one hundred two thousand, five hundred three".
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