Base | Representation |
---|---|
bin | 1011111100011100100111… |
… | …1100111111000101001111 |
3 | 1201111111211112201020222022 |
4 | 2333013021330333011033 |
5 | 3210133043411400221 |
6 | 43533133032440355 |
7 | 2523556353402350 |
oct | 277071174770517 |
9 | 51444745636868 |
10 | 13133103231311 |
11 | 42037994384a8 |
12 | 15813498490bb |
13 | 7435a574999b |
14 | 3359076c9d27 |
15 | 17b94eb814ab |
hex | bf1c9f3f14f |
13133103231311 has 4 divisors (see below), whose sum is σ = 15009260835792. Its totient is φ = 11256945626832.
The previous prime is 13133103231277. The next prime is 13133103231319. The reversal of 13133103231311 is 11313230133131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13133103231311 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13133103231319) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 938078802230 + ... + 938078802243.
It is an arithmetic number, because the mean of its divisors is an integer number (3752315208948).
Almost surely, 213133103231311 is an apocalyptic number.
13133103231311 is a deficient number, since it is larger than the sum of its proper divisors (1876157604481).
13133103231311 is an equidigital number, since it uses as much as digits as its factorization.
13133103231311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1876157604480.
The product of its (nonzero) digits is 1458, while the sum is 26.
Adding to 13133103231311 its reverse (11313230133131), we get a palindrome (24446333364442).
The spelling of 13133103231311 in words is "thirteen trillion, one hundred thirty-three billion, one hundred three million, two hundred thirty-one thousand, three hundred eleven".
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