Base | Representation |
---|---|
bin | 11000011101100101… |
… | …10111100011101101 |
3 | 1020220021021111120211 |
4 | 30032302313203231 |
5 | 203344034231202 |
6 | 10011104142421 |
7 | 643310441551 |
oct | 141662674355 |
9 | 36807244524 |
10 | 13133117677 |
11 | 562a336769 |
12 | 2666307a11 |
13 | 1313b3c564 |
14 | 8c82db861 |
15 | 51ce991d7 |
hex | 30ecb78ed |
13133117677 has 2 divisors, whose sum is σ = 13133117678. Its totient is φ = 13133117676.
The previous prime is 13133117659. The next prime is 13133117681. The reversal of 13133117677 is 77671133131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13022004996 + 111112681 = 114114^2 + 10541^2 .
It is an emirp because it is prime and its reverse (77671133131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13133117677 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13133117617) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566558838 + 6566558839.
It is an arithmetic number, because the mean of its divisors is an integer number (6566558839).
Almost surely, 213133117677 is an apocalyptic number.
It is an amenable number.
13133117677 is a deficient number, since it is larger than the sum of its proper divisors (1).
13133117677 is an equidigital number, since it uses as much as digits as its factorization.
13133117677 is an evil number, because the sum of its binary digits is even.
The product of its digits is 55566, while the sum is 40.
The spelling of 13133117677 in words is "thirteen billion, one hundred thirty-three million, one hundred seventeen thousand, six hundred seventy-seven".
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