Base | Representation |
---|---|
bin | 1011111100011100101100… |
… | …0100111110100000000110 |
3 | 1201111111212212020001110221 |
4 | 2333013023010332200012 |
5 | 3210133113224301202 |
6 | 43533134545134554 |
7 | 2523560002662625 |
oct | 277071304764006 |
9 | 51444785201427 |
10 | 13133122103302 |
11 | 42037a9058293 |
12 | 158135402a45a |
13 | 7435a9626846 |
14 | 335909ddd6bc |
15 | 17b95165d037 |
hex | bf1cb13e806 |
13133122103302 has 4 divisors (see below), whose sum is σ = 19699683154956. Its totient is φ = 6566561051650.
The previous prime is 13133122103237. The next prime is 13133122103323. The reversal of 13133122103302 is 20330122133131.
13133122103302 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×131331221033023 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3283280525824 + ... + 3283280525827.
It is an arithmetic number, because the mean of its divisors is an integer number (4924920788739).
Almost surely, 213133122103302 is an apocalyptic number.
13133122103302 is a deficient number, since it is larger than the sum of its proper divisors (6566561051654).
13133122103302 is an equidigital number, since it uses as much as digits as its factorization.
13133122103302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6566561051653.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 13133122103302 its reverse (20330122133131), we get a palindrome (33463244236433).
The spelling of 13133122103302 in words is "thirteen trillion, one hundred thirty-three billion, one hundred twenty-two million, one hundred three thousand, three hundred two".
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