Base | Representation |
---|---|
bin | 1011111100011100101100… |
… | …1000011110010110111111 |
3 | 1201111111212220221122020222 |
4 | 2333013023020132112333 |
5 | 3210133113443121343 |
6 | 43533135020531555 |
7 | 2523560013532103 |
oct | 277071310362677 |
9 | 51444786848228 |
10 | 13133123020223 |
11 | 42037a9624178 |
12 | 15813543b0bbb |
13 | 7435a9887cbb |
14 | 33590a19b903 |
15 | 17b95178ea68 |
hex | bf1cb21e5bf |
13133123020223 has 2 divisors, whose sum is σ = 13133123020224. Its totient is φ = 13133123020222.
The previous prime is 13133123020099. The next prime is 13133123020309. The reversal of 13133123020223 is 32202032133131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13133123020223 - 220 = 13133121971647 is a prime.
It is a super-2 number, since 2×131331230202232 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13133123020192 and 13133123020201.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13133123025223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566561510111 + 6566561510112.
It is an arithmetic number, because the mean of its divisors is an integer number (6566561510112).
Almost surely, 213133123020223 is an apocalyptic number.
13133123020223 is a deficient number, since it is larger than the sum of its proper divisors (1).
13133123020223 is an equidigital number, since it uses as much as digits as its factorization.
13133123020223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 26.
Adding to 13133123020223 its reverse (32202032133131), we get a palindrome (45335155153354).
The spelling of 13133123020223 in words is "thirteen trillion, one hundred thirty-three billion, one hundred twenty-three million, twenty thousand, two hundred twenty-three".
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