Base | Representation |
---|---|
bin | 11101110111000111111010… |
… | …101100100101001011000111 |
3 | 122020000011100112111221110012 |
4 | 131313013322230211023013 |
5 | 114203213222234003031 |
6 | 1143152453310420435 |
7 | 36443245020401243 |
oct | 3567077254451307 |
9 | 566004315457405 |
10 | 131331421000391 |
11 | 38934385396037 |
12 | 12890aab20171b |
13 | 5838666266a41 |
14 | 24606907ad423 |
15 | 102b371c39b2b |
hex | 7771fab252c7 |
131331421000391 has 4 divisors (see below), whose sum is σ = 131341586770800. Its totient is φ = 131321255229984.
The previous prime is 131331421000361. The next prime is 131331421000397. The reversal of 131331421000391 is 193000124133131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131331421000391 - 222 = 131331416806087 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131331421000397) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5082865826 + ... + 5082891663.
It is an arithmetic number, because the mean of its divisors is an integer number (32835396692700).
Almost surely, 2131331421000391 is an apocalyptic number.
131331421000391 is a deficient number, since it is larger than the sum of its proper divisors (10165770409).
131331421000391 is a wasteful number, since it uses less digits than its factorization.
131331421000391 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10165770408.
The product of its (nonzero) digits is 5832, while the sum is 32.
The spelling of 131331421000391 in words is "one hundred thirty-one trillion, three hundred thirty-one billion, four hundred twenty-one million, three hundred ninety-one", and thus it is an aban number.
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