Base | Representation |
---|---|
bin | 1011111100011101000001… |
… | …1000111011110000011111 |
3 | 1201111112010001220201000021 |
4 | 2333013100120323300133 |
5 | 3210133304033033043 |
6 | 43533151451213011 |
7 | 2523562134322225 |
oct | 277072030736037 |
9 | 51445101821007 |
10 | 13133211221023 |
11 | 42038443967a3 |
12 | 1581379a47167 |
13 | 7435c1c2a01a |
14 | 335917b9ab15 |
15 | 17b9593b33ed |
hex | bf1d063bc1f |
13133211221023 has 4 divisors (see below), whose sum is σ = 13453533445968. Its totient is φ = 12812888996080.
The previous prime is 13133211220949. The next prime is 13133211221041. The reversal of 13133211221023 is 32012211233131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13133211221023 - 213 = 13133211212831 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13133211221623) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160161112411 + ... + 160161112492.
It is an arithmetic number, because the mean of its divisors is an integer number (3363383361492).
Almost surely, 213133211221023 is an apocalyptic number.
13133211221023 is a deficient number, since it is larger than the sum of its proper divisors (320322224945).
13133211221023 is an equidigital number, since it uses as much as digits as its factorization.
13133211221023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 320322224944.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13133211221023 its reverse (32012211233131), we get a palindrome (45145422454154).
The spelling of 13133211221023 in words is "thirteen trillion, one hundred thirty-three billion, two hundred eleven million, two hundred twenty-one thousand, twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •