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13133222114 = 26566611057
BaseRepresentation
bin11000011101100110…
…10001000011100010
31020220021110210211212
430032303101003202
5203344101101424
610011110310122
7643311355205
oct141663210342
936807423755
1013133222114
11562a3a8181
122666358342
131313b77c5c
148c832793c
1551ceba10e
hex30ecd10e2

13133222114 has 4 divisors (see below), whose sum is σ = 19699833174. Its totient is φ = 6566611056.

The previous prime is 13133222099. The next prime is 13133222117. The reversal of 13133222114 is 41122233131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 7352205025 + 5781017089 = 85745^2 + 76033^2 .

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 13133222114.

It is not an unprimeable number, because it can be changed into a prime (13133222117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3283305527 + ... + 3283305530.

Almost surely, 213133222114 is an apocalyptic number.

13133222114 is a deficient number, since it is larger than the sum of its proper divisors (6566611060).

13133222114 is an equidigital number, since it uses as much as digits as its factorization.

13133222114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6566611059.

The product of its digits is 864, while the sum is 23.

Adding to 13133222114 its reverse (41122233131), we get a palindrome (54255455245).

The spelling of 13133222114 in words is "thirteen billion, one hundred thirty-three million, two hundred twenty-two thousand, one hundred fourteen".

Divisors: 1 2 6566611057 13133222114