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13133225202242 = 26566612601121
BaseRepresentation
bin1011111100011101000100…
…1110010001001001000010
31201111112011001020000122012
42333013101032101021002
53210133321122432432
643533153111012522
72523562364212625
oct277072116211102
951445131200565
1013133225202242
114203851276022
12158138266a142
137435c4ab3a32
14335919999dbc
1517b95a725cb2
hexbf1d1391242

13133225202242 has 4 divisors (see below), whose sum is σ = 19699837803366. Its totient is φ = 6566612601120.

The previous prime is 13133225202221. The next prime is 13133225202277. The reversal of 13133225202242 is 24220252233131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 13113893358721 + 19331843521 = 3621311^2 + 139039^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13133225202199 and 13133225202208.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3283306300559 + ... + 3283306300562.

Almost surely, 213133225202242 is an apocalyptic number.

13133225202242 is a deficient number, since it is larger than the sum of its proper divisors (6566612601124).

13133225202242 is an equidigital number, since it uses as much as digits as its factorization.

13133225202242 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6566612601123.

The product of its (nonzero) digits is 34560, while the sum is 32.

Adding to 13133225202242 its reverse (24220252233131), we get a palindrome (37353477435373).

The spelling of 13133225202242 in words is "thirteen trillion, one hundred thirty-three billion, two hundred twenty-five million, two hundred two thousand, two hundred forty-two".

Divisors: 1 2 6566612601121 13133225202242