Base | Representation |
---|---|
bin | 1011111100011101000100… |
… | …1110010001001001000010 |
3 | 1201111112011001020000122012 |
4 | 2333013101032101021002 |
5 | 3210133321122432432 |
6 | 43533153111012522 |
7 | 2523562364212625 |
oct | 277072116211102 |
9 | 51445131200565 |
10 | 13133225202242 |
11 | 4203851276022 |
12 | 158138266a142 |
13 | 7435c4ab3a32 |
14 | 335919999dbc |
15 | 17b95a725cb2 |
hex | bf1d1391242 |
13133225202242 has 4 divisors (see below), whose sum is σ = 19699837803366. Its totient is φ = 6566612601120.
The previous prime is 13133225202221. The next prime is 13133225202277. The reversal of 13133225202242 is 24220252233131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 13113893358721 + 19331843521 = 3621311^2 + 139039^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13133225202199 and 13133225202208.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3283306300559 + ... + 3283306300562.
Almost surely, 213133225202242 is an apocalyptic number.
13133225202242 is a deficient number, since it is larger than the sum of its proper divisors (6566612601124).
13133225202242 is an equidigital number, since it uses as much as digits as its factorization.
13133225202242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6566612601123.
The product of its (nonzero) digits is 34560, while the sum is 32.
Adding to 13133225202242 its reverse (24220252233131), we get a palindrome (37353477435373).
The spelling of 13133225202242 in words is "thirteen trillion, one hundred thirty-three billion, two hundred twenty-five million, two hundred two thousand, two hundred forty-two".
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