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131332521542477 is a prime number
BaseRepresentation
bin11101110111001000111100…
…010010110100001101001101
3122020000021012020101021101012
4131313020330102310031031
5114203223001003324402
61143153154423055005
736443314213012613
oct3567107422641515
9566007166337335
10131332521542477
113893489a640652
12128911578a1465
1358387b0277388
142460756a0d6b3
15102b3d867b452
hex77723c4b434d

131332521542477 has 2 divisors, whose sum is σ = 131332521542478. Its totient is φ = 131332521542476.

The previous prime is 131332521542471. The next prime is 131332521542507. The reversal of 131332521542477 is 774245125233131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 112532761557316 + 18799759985161 = 10608146^2 + 4335869^2 .

It is a cyclic number.

It is not a de Polignac number, because 131332521542477 - 218 = 131332521280333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131332521542471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65666260771238 + 65666260771239.

It is an arithmetic number, because the mean of its divisors is an integer number (65666260771239).

Almost surely, 2131332521542477 is an apocalyptic number.

It is an amenable number.

131332521542477 is a deficient number, since it is larger than the sum of its proper divisors (1).

131332521542477 is an equidigital number, since it uses as much as digits as its factorization.

131332521542477 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4233600, while the sum is 50.

The spelling of 131332521542477 in words is "one hundred thirty-one trillion, three hundred thirty-two billion, five hundred twenty-one million, five hundred forty-two thousand, four hundred seventy-seven".