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131332521544537 is a prime number
BaseRepresentation
bin11101110111001000111100…
…010010110100101101011001
3122020000021012020101101012111
4131313020330102310231121
5114203223001003411122
61143153154423112321
736443314213021615
oct3567107422645531
9566007166341174
10131332521544537
113893489a642155
12128911578a26a1
1358387b02782b1
142460756a10345
15102b3d867bd77
hex77723c4b4b59

131332521544537 has 2 divisors, whose sum is σ = 131332521544538. Its totient is φ = 131332521544536.

The previous prime is 131332521544463. The next prime is 131332521544597. The reversal of 131332521544537 is 735445125233131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112625071350016 + 18707450194521 = 10612496^2 + 4325211^2 .

It is a cyclic number.

It is not a de Polignac number, because 131332521544537 - 231 = 131330374060889 is a prime.

It is not a weakly prime, because it can be changed into another prime (131332521544597) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65666260772268 + 65666260772269.

It is an arithmetic number, because the mean of its divisors is an integer number (65666260772269).

Almost surely, 2131332521544537 is an apocalyptic number.

It is an amenable number.

131332521544537 is a deficient number, since it is larger than the sum of its proper divisors (1).

131332521544537 is an equidigital number, since it uses as much as digits as its factorization.

131332521544537 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4536000, while the sum is 49.

Adding to 131332521544537 its reverse (735445125233131), we get a palindrome (866777646777668).

The spelling of 131332521544537 in words is "one hundred thirty-one trillion, three hundred thirty-two billion, five hundred twenty-one million, five hundred forty-four thousand, five hundred thirty-seven".