Base | Representation |
---|---|
bin | 11101110111001000111100… |
… | …010010110100101101011001 |
3 | 122020000021012020101101012111 |
4 | 131313020330102310231121 |
5 | 114203223001003411122 |
6 | 1143153154423112321 |
7 | 36443314213021615 |
oct | 3567107422645531 |
9 | 566007166341174 |
10 | 131332521544537 |
11 | 3893489a642155 |
12 | 128911578a26a1 |
13 | 58387b02782b1 |
14 | 2460756a10345 |
15 | 102b3d867bd77 |
hex | 77723c4b4b59 |
131332521544537 has 2 divisors, whose sum is σ = 131332521544538. Its totient is φ = 131332521544536.
The previous prime is 131332521544463. The next prime is 131332521544597. The reversal of 131332521544537 is 735445125233131.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 112625071350016 + 18707450194521 = 10612496^2 + 4325211^2 .
It is a cyclic number.
It is not a de Polignac number, because 131332521544537 - 231 = 131330374060889 is a prime.
It is not a weakly prime, because it can be changed into another prime (131332521544597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65666260772268 + 65666260772269.
It is an arithmetic number, because the mean of its divisors is an integer number (65666260772269).
Almost surely, 2131332521544537 is an apocalyptic number.
It is an amenable number.
131332521544537 is a deficient number, since it is larger than the sum of its proper divisors (1).
131332521544537 is an equidigital number, since it uses as much as digits as its factorization.
131332521544537 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4536000, while the sum is 49.
Adding to 131332521544537 its reverse (735445125233131), we get a palindrome (866777646777668).
The spelling of 131332521544537 in words is "one hundred thirty-one trillion, three hundred thirty-two billion, five hundred twenty-one million, five hundred forty-four thousand, five hundred thirty-seven".
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