Base | Representation |
---|---|
bin | 11101110111001001011110… |
… | …110010010101100111000011 |
3 | 122020000022200120021200221102 |
4 | 131313021132302111213003 |
5 | 114203230142124343412 |
6 | 1143153332054245015 |
7 | 36443334440541515 |
oct | 3567113662254703 |
9 | 566008616250842 |
10 | 131333100231107 |
11 | 38935067262a15 |
12 | 1289129965676b |
13 | 5838873120998 |
14 | 24607ad809bb5 |
15 | 102b41e3898c2 |
hex | 77725ec959c3 |
131333100231107 has 2 divisors, whose sum is σ = 131333100231108. Its totient is φ = 131333100231106.
The previous prime is 131333100231101. The next prime is 131333100231121. The reversal of 131333100231107 is 701132001333131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131333100231107 - 28 = 131333100230851 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131333100231107.
It is not a weakly prime, because it can be changed into another prime (131333100231101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65666550115553 + 65666550115554.
It is an arithmetic number, because the mean of its divisors is an integer number (65666550115554).
Almost surely, 2131333100231107 is an apocalyptic number.
131333100231107 is a deficient number, since it is larger than the sum of its proper divisors (1).
131333100231107 is an equidigital number, since it uses as much as digits as its factorization.
131333100231107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3402, while the sum is 29.
Adding to 131333100231107 its reverse (701132001333131), we get a palindrome (832465101564238).
The spelling of 131333100231107 in words is "one hundred thirty-one trillion, three hundred thirty-three billion, one hundred million, two hundred thirty-one thousand, one hundred seven".
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