Base | Representation |
---|---|
bin | 10011000111001000101… |
… | …000010000010110101111 |
3 | 11122112221022000111110020 |
4 | 103013020220100112233 |
5 | 133004200220134411 |
6 | 2443200321413223 |
7 | 163612365326445 |
oct | 23071050202657 |
9 | 4575838014406 |
10 | 1313331021231 |
11 | 466a87139809 |
12 | 192647a9a213 |
13 | 96b00c38998 |
14 | 477cbc80b95 |
15 | 24269462606 |
hex | 131c8a105af |
1313331021231 has 4 divisors (see below), whose sum is σ = 1751108028312. Its totient is φ = 875554014152.
The previous prime is 1313331021229. The next prime is 1313331021263. The reversal of 1313331021231 is 1321201333131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1313331021231 - 21 = 1313331021229 is a prime.
It is a super-2 number, since 2×13133310212312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1313331021731) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218888503536 + ... + 218888503541.
It is an arithmetic number, because the mean of its divisors is an integer number (437777007078).
Almost surely, 21313331021231 is an apocalyptic number.
1313331021231 is a deficient number, since it is larger than the sum of its proper divisors (437777007081).
1313331021231 is an equidigital number, since it uses as much as digits as its factorization.
1313331021231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 437777007080.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 1313331021231 its reverse (1321201333131), we get a palindrome (2634532354362).
The spelling of 1313331021231 in words is "one trillion, three hundred thirteen billion, three hundred thirty-one million, twenty-one thousand, two hundred thirty-one".
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