Base | Representation |
---|---|
bin | 11101110111001001100001… |
… | …001110011001101100001011 |
3 | 122020000022210102021012112011 |
4 | 131313021201032121230023 |
5 | 114203230233113023113 |
6 | 1143153340115200351 |
7 | 36443335445353213 |
oct | 3567114116315413 |
9 | 566008712235464 |
10 | 131333141142283 |
11 | 38935088366103 |
12 | 128912ab2a60b7 |
13 | 583887b746192 |
14 | 24607b5019243 |
15 | 102b422c6b63d |
hex | 777261399b0b |
131333141142283 has 2 divisors, whose sum is σ = 131333141142284. Its totient is φ = 131333141142282.
The previous prime is 131333141142277. The next prime is 131333141142331. The reversal of 131333141142283 is 382241141333131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131333141142283 is a prime.
It is not a weakly prime, because it can be changed into another prime (131333141149283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65666570571141 + 65666570571142.
It is an arithmetic number, because the mean of its divisors is an integer number (65666570571142).
Almost surely, 2131333141142283 is an apocalyptic number.
131333141142283 is a deficient number, since it is larger than the sum of its proper divisors (1).
131333141142283 is an equidigital number, since it uses as much as digits as its factorization.
131333141142283 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 124416, while the sum is 40.
The spelling of 131333141142283 in words is "one hundred thirty-one trillion, three hundred thirty-three billion, one hundred forty-one million, one hundred forty-two thousand, two hundred eighty-three".
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