Base | Representation |
---|---|
bin | 11101110111001001100001… |
… | …001110011001101100111011 |
3 | 122020000022210102021012120221 |
4 | 131313021201032121230323 |
5 | 114203230233113023311 |
6 | 1143153340115200511 |
7 | 36443335445353312 |
oct | 3567114116315473 |
9 | 566008712235527 |
10 | 131333141142331 |
11 | 38935088366147 |
12 | 128912ab2a6137 |
13 | 583887b7461cb |
14 | 24607b5019279 |
15 | 102b422c6b671 |
hex | 777261399b3b |
131333141142331 has 2 divisors, whose sum is σ = 131333141142332. Its totient is φ = 131333141142330.
The previous prime is 131333141142283. The next prime is 131333141142347. The reversal of 131333141142331 is 133241141333131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131333141142331 - 235 = 131298781403963 is a prime.
It is a super-2 number, since 2×1313331411423312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131333141145331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65666570571165 + 65666570571166.
It is an arithmetic number, because the mean of its divisors is an integer number (65666570571166).
Almost surely, 2131333141142331 is an apocalyptic number.
131333141142331 is a deficient number, since it is larger than the sum of its proper divisors (1).
131333141142331 is an equidigital number, since it uses as much as digits as its factorization.
131333141142331 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 23328, while the sum is 34.
Adding to 131333141142331 its reverse (133241141333131), we get a palindrome (264574282475462).
The spelling of 131333141142331 in words is "one hundred thirty-one trillion, three hundred thirty-three billion, one hundred forty-one million, one hundred forty-two thousand, three hundred thirty-one".
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