Base | Representation |
---|---|
bin | 11101110111001001101010… |
… | …101100110100011101111110 |
3 | 122020000100012111101122220221 |
4 | 131313021222230310131332 |
5 | 114203231044312024410 |
6 | 1143153403554331554 |
7 | 36443342415516430 |
oct | 3567115254643576 |
9 | 566010174348827 |
10 | 131333300111230 |
11 | 3893515a0738a8 |
12 | 12891334589bba |
13 | 58388a5665549 |
14 | 24607cc19a650 |
15 | 102b431bbd4da |
hex | 77726ab3477e |
131333300111230 has 64 divisors (see below), whose sum is σ = 270609134902272. Its totient is φ = 44955608014080.
The previous prime is 131333300111191. The next prime is 131333300111269. The reversal of 131333300111230 is 32111003333131.
131333300111230 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (131333300111191) and next prime (131333300111269).
It is a super-2 number, since 2×1313333001112302 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131333300111195 and 131333300111204.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 649674570 + ... + 649876690.
It is an arithmetic number, because the mean of its divisors is an integer number (4228267732848).
Almost surely, 2131333300111230 is an apocalyptic number.
131333300111230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131333300111230 is an abundant number, since it is smaller than the sum of its proper divisors (139275834791042).
131333300111230 is a wasteful number, since it uses less digits than its factorization.
131333300111230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 217129.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 131333300111230 its reverse (32111003333131), we get a palindrome (163444303444361).
The spelling of 131333300111230 in words is "one hundred thirty-one trillion, three hundred thirty-three billion, three hundred million, one hundred eleven thousand, two hundred thirty".
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