1313340433130 has 32 divisors (see below), whose sum is σ = 2579170889088. Its totient is φ = 477532440000.

The previous prime is 1313340433121. The next prime is 1313340433187. The reversal of 1313340433130 is 313340433131.

It is a junction number, because it is equal to n+sod(n) for n = 1313340433093 and 1313340433102.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 586619 + ... + 1723601.

It is an arithmetic number, because the mean of its divisors is an integer number (80599090284).

Almost surely, 2^{1313340433130} is an apocalyptic number.

1313340433130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1313340433130 is a deficient number, since it is larger than the sum of its proper divisors (1265830455958).

1313340433130 is a wasteful number, since it uses less digits than its factorization.

1313340433130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1147502.

The product of its (nonzero) digits is 11664, while the sum is 29.

Adding to 1313340433130 its reverse (313340433131), we get a palindrome (1626680866261).

Subtracting from 1313340433130 its reverse (313340433131), we obtain a palindrome (999999999999).

The spelling of 1313340433130 in words is "one trillion, three hundred thirteen billion, three hundred forty million, four hundred thirty-three thousand, one hundred thirty".