Base | Representation |
---|---|
bin | 10011000111001001001… |
… | …111010100001011110111 |
3 | 11122112222000021201010201 |
4 | 103013021033110023313 |
5 | 133004210330314120 |
6 | 2443201325101331 |
7 | 163612551343603 |
oct | 23071117241367 |
9 | 4575860251121 |
10 | 1313341260535 |
11 | 466a919a2747 |
12 | 19264b3b7847 |
13 | 96b030b2445 |
14 | 477cd388503 |
15 | 2426a2d640a |
hex | 131c93d42f7 |
1313341260535 has 16 divisors (see below), whose sum is σ = 1606291236000. Its totient is φ = 1030564519936.
The previous prime is 1313341260529. The next prime is 1313341260571. The reversal of 1313341260535 is 5350621433131.
It is a cyclic number.
It is not a de Polignac number, because 1313341260535 - 213 = 1313341252343 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1313341260494 and 1313341260503.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4825234 + ... + 5090143.
It is an arithmetic number, because the mean of its divisors is an integer number (100393202250).
Almost surely, 21313341260535 is an apocalyptic number.
1313341260535 is a deficient number, since it is larger than the sum of its proper divisors (292949975465).
1313341260535 is an equidigital number, since it uses as much as digits as its factorization.
1313341260535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9915890.
The product of its (nonzero) digits is 97200, while the sum is 37.
Adding to 1313341260535 its reverse (5350621433131), we get a palindrome (6663962693666).
The spelling of 1313341260535 in words is "one trillion, three hundred thirteen billion, three hundred forty-one million, two hundred sixty thousand, five hundred thirty-five".
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