1313342441401 has 2 divisors, whose sum is σ = 1313342441402. Its totient is φ = 1313342441400.

The previous prime is 1313342441399. The next prime is 1313342441507. The reversal of 1313342441401 is 1041442433131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 768469637376 + 544872804025 = 876624^2 + 738155^2 .

It is a cyclic number.

It is not a de Polignac number, because 1313342441401 - 2¹ = 1313342441399 is a prime.

Together with 1313342441399, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1313342448401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656671220700 + 656671220701.

It is an arithmetic number, because the mean of its divisors is an integer number (656671220701).

Almost surely, 2^{1313342441401} is an apocalyptic number.

It is an amenable number.

1313342441401 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313342441401 is an equidigital number, since it uses as much as digits as its factorization.

1313342441401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 1313342441401 its reverse (1041442433131), we get a palindrome (2354784874532).

The spelling of 1313342441401 in words is "one trillion, three hundred thirteen billion, three hundred forty-two million, four hundred forty-one thousand, four hundred one".