Base | Representation |
---|---|
bin | 1011111100011110001110… |
… | …0110011101001111011111 |
3 | 1201111112221112101212010111 |
4 | 2333013203212131033133 |
5 | 3210134434041030101 |
6 | 43533243443350451 |
7 | 2523603130040563 |
oct | 277074346351737 |
9 | 51445845355114 |
10 | 13133533533151 |
11 | 420399a31a659 |
12 | 1581449982427 |
13 | 74364393a765 |
14 | 3359488db6a3 |
15 | 17b97782d251 |
hex | bf1e399d3df |
13133533533151 has 2 divisors, whose sum is σ = 13133533533152. Its totient is φ = 13133533533150.
The previous prime is 13133533533097. The next prime is 13133533533167. The reversal of 13133533533151 is 15133533533131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13133533533151 - 213 = 13133533524959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13133533533251) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566766766575 + 6566766766576.
It is an arithmetic number, because the mean of its divisors is an integer number (6566766766576).
Almost surely, 213133533533151 is an apocalyptic number.
13133533533151 is a deficient number, since it is larger than the sum of its proper divisors (1).
13133533533151 is an equidigital number, since it uses as much as digits as its factorization.
13133533533151 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 273375, while the sum is 40.
The spelling of 13133533533151 in words is "thirteen trillion, one hundred thirty-three billion, five hundred thirty-three million, five hundred thirty-three thousand, one hundred fifty-one".
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