Base | Representation |
---|---|
bin | 10011000111001100110… |
… | …011101010011011110111 |
3 | 11122120010011220220120120 |
4 | 103013030303222123313 |
5 | 133004321141324003 |
6 | 2443211304103023 |
7 | 163614206215503 |
oct | 23071463523367 |
9 | 4576104826516 |
10 | 1313401120503 |
11 | 46701276839a |
12 | 192667464a73 |
13 | 96b12610744 |
14 | 477d72cb303 |
15 | 242706ac853 |
hex | 131cccea6f7 |
1313401120503 has 8 divisors (see below), whose sum is σ = 1751222002416. Its totient is φ = 875590492800.
The previous prime is 1313401120469. The next prime is 1313401120513. The reversal of 1313401120503 is 3050211043131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1313401120503 - 29 = 1313401119991 is a prime.
It is a super-3 number, since 3×13134011205033 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1313401120513) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2259538 + ... + 2780703.
It is an arithmetic number, because the mean of its divisors is an integer number (218902750302).
Almost surely, 21313401120503 is an apocalyptic number.
1313401120503 is a deficient number, since it is larger than the sum of its proper divisors (437820881913).
1313401120503 is an equidigital number, since it uses as much as digits as its factorization.
1313401120503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5127105.
The product of its (nonzero) digits is 1080, while the sum is 24.
Adding to 1313401120503 its reverse (3050211043131), we get a palindrome (4363612163634).
The spelling of 1313401120503 in words is "one trillion, three hundred thirteen billion, four hundred one million, one hundred twenty thousand, five hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •