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13134012103 = 104947125149
BaseRepresentation
bin11000011101101100…
…10001111011000111
31020220022221221111201
430032312101323013
5203344301341403
610011135243331
7643321155322
oct141666217307
936808857451
1013134012103
11562a897763
122666679547
1313140936c4
148c84917b9
1551d0c421d
hex30ed91ec7

13134012103 has 4 divisors (see below), whose sum is σ = 13134242200. Its totient is φ = 13133782008.

The previous prime is 13134012083. The next prime is 13134012107. The reversal of 13134012103 is 30121043131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13134012103 - 25 = 13134012071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13134012107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42373 + ... + 167521.

It is an arithmetic number, because the mean of its divisors is an integer number (3283560550).

Almost surely, 213134012103 is an apocalyptic number.

13134012103 is a deficient number, since it is larger than the sum of its proper divisors (230097).

13134012103 is a wasteful number, since it uses less digits than its factorization.

13134012103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 230096.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13134012103 its reverse (30121043131), we get a palindrome (43255055234).

The spelling of 13134012103 in words is "thirteen billion, one hundred thirty-four million, twelve thousand, one hundred three".

Divisors: 1 104947 125149 13134012103