Base | Representation |
---|---|
bin | 11000011101101100… |
… | …10001111011011111 |
3 | 1020220022221221112121 |
4 | 30032312101323133 |
5 | 203344301342002 |
6 | 10011135243411 |
7 | 643321155355 |
oct | 141666217337 |
9 | 36808857477 |
10 | 13134012127 |
11 | 562a897785 |
12 | 2666679567 |
13 | 1314093712 |
14 | 8c84917d5 |
15 | 51d0c4237 |
hex | 30ed91edf |
13134012127 has 2 divisors, whose sum is σ = 13134012128. Its totient is φ = 13134012126.
The previous prime is 13134012107. The next prime is 13134012173. The reversal of 13134012127 is 72121043131.
It is a weak prime.
It is an emirp because it is prime and its reverse (72121043131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13134012127 - 215 = 13133979359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13134012107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567006063 + 6567006064.
It is an arithmetic number, because the mean of its divisors is an integer number (6567006064).
Almost surely, 213134012127 is an apocalyptic number.
13134012127 is a deficient number, since it is larger than the sum of its proper divisors (1).
13134012127 is an equidigital number, since it uses as much as digits as its factorization.
13134012127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 13134012127 its reverse (72121043131), we get a palindrome (85255055258).
The spelling of 13134012127 in words is "thirteen billion, one hundred thirty-four million, twelve thousand, one hundred twenty-seven".
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