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13134020353 is a prime number
BaseRepresentation
bin11000011101101100…
…10011111100000001
31020220022222100211021
430032312103330001
5203344302122403
610011135345441
7643321221346
oct141666237401
936808870737
1013134020353
11562a8a2983
122666682281
13131409739c
148c84947cd
1551d0c68bd
hex30ed93f01

13134020353 has 2 divisors, whose sum is σ = 13134020354. Its totient is φ = 13134020352.

The previous prime is 13134020329. The next prime is 13134020359. The reversal of 13134020353 is 35302043131.

13134020353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13038899344 + 95121009 = 114188^2 + 9753^2 .

It is a cyclic number.

It is not a de Polignac number, because 13134020353 - 217 = 13133889281 is a prime.

It is not a weakly prime, because it can be changed into another prime (13134020359) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567010176 + 6567010177.

It is an arithmetic number, because the mean of its divisors is an integer number (6567010177).

Almost surely, 213134020353 is an apocalyptic number.

It is an amenable number.

13134020353 is a deficient number, since it is larger than the sum of its proper divisors (1).

13134020353 is an equidigital number, since it uses as much as digits as its factorization.

13134020353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3240, while the sum is 25.

Adding to 13134020353 its reverse (35302043131), we get a palindrome (48436063484).

The spelling of 13134020353 in words is "thirteen billion, one hundred thirty-four million, twenty thousand, three hundred fifty-three".