Base | Representation |
---|---|
bin | 1011111100100000000010… |
… | …1011100100011011000000 |
3 | 1201111121012112102200211122 |
4 | 2333020000223210123000 |
5 | 3210141433440200134 |
6 | 43533404112331412 |
7 | 2523621202663514 |
oct | 277100053443300 |
9 | 51447175380748 |
10 | 13134021412544 |
11 | 420411a75866a |
12 | 1581565243b68 |
13 | 7436c0a3a9a6 |
14 | 33599361a144 |
15 | 17b9a55a002e |
hex | bf200ae46c0 |
13134021412544 has 56 divisors (see below), whose sum is σ = 26535285227520. Its totient is φ = 6448223300864.
The previous prime is 13134021412357. The next prime is 13134021412601. The reversal of 13134021412544 is 44521412043131.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1243457 + ... + 5273919.
Almost surely, 213134021412544 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13134021412544, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (13267642613760).
13134021412544 is an abundant number, since it is smaller than the sum of its proper divisors (13401263814976).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13134021412544 is an equidigital number, since it uses as much as digits as its factorization.
13134021412544 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4031397 (or 4031387 counting only the distinct ones).
The product of its (nonzero) digits is 46080, while the sum is 35.
Adding to 13134021412544 its reverse (44521412043131), we get a palindrome (57655433455675).
The spelling of 13134021412544 in words is "thirteen trillion, one hundred thirty-four billion, twenty-one million, four hundred twelve thousand, five hundred forty-four".
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