1313403513413 has 4 divisors (see below), whose sum is σ = 1316240238528. Its totient is φ = 1310566788300.

The previous prime is 1313403513407. The next prime is 1313403513419. The reversal of 1313403513413 is 3143153043131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (1313403513407) and next prime (1313403513419).

It is a cyclic number.

It is not a de Polignac number, because 1313403513413 - 2³² = 1309108546117 is a prime.

It is a super-2 number, since 2×1313403513413² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1313403513413.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1313403513419) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1418361863 + ... + 1418362788.

It is an arithmetic number, because the mean of its divisors is an integer number (329060059632).

Almost surely, 2^{1313403513413} is an apocalyptic number.

It is an amenable number.

1313403513413 is a deficient number, since it is larger than the sum of its proper divisors (2836725115).

1313403513413 is an equidigital number, since it uses as much as digits as its factorization.

1313403513413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2836725114.

The product of its (nonzero) digits is 19440, while the sum is 32.

Adding to 1313403513413 its reverse (3143153043131), we get a palindrome (4456556556544).

The spelling of 1313403513413 in words is "one trillion, three hundred thirteen billion, four hundred three million, five hundred thirteen thousand, four hundred thirteen".