Base | Representation |
---|---|
bin | 10011000111001101011… |
… | …001100001001101011101 |
3 | 11122120010212121002022111 |
4 | 103013031121201031131 |
5 | 133004331211403224 |
6 | 2443212300514021 |
7 | 163614356446516 |
oct | 23071531411535 |
9 | 4576125532274 |
10 | 1313411044189 |
11 | 467018326192 |
12 | 19266a84b911 |
13 | 96b146a664a |
14 | 477d8751a0d |
15 | 242714bcd94 |
hex | 131cd66135d |
1313411044189 has 2 divisors, whose sum is σ = 1313411044190. Its totient is φ = 1313411044188.
The previous prime is 1313411044181. The next prime is 1313411044223. The reversal of 1313411044189 is 9814401143131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 730529184100 + 582881860089 = 854710^2 + 763467^2 .
It is a cyclic number.
It is not a de Polignac number, because 1313411044189 - 23 = 1313411044181 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313411044181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656705522094 + 656705522095.
It is an arithmetic number, because the mean of its divisors is an integer number (656705522095).
Almost surely, 21313411044189 is an apocalyptic number.
It is an amenable number.
1313411044189 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313411044189 is an equidigital number, since it uses as much as digits as its factorization.
1313411044189 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 40.
The spelling of 1313411044189 in words is "one trillion, three hundred thirteen billion, four hundred eleven million, forty-four thousand, one hundred eighty-nine".
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