13134113 has 2 divisors, whose sum is σ = 13134114. Its totient is φ = 13134112.

The previous prime is 13134101. The next prime is 13134137. The reversal of 13134113 is 31143131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6697744 + 6436369 = 2588^2 + 2537^2 .

It is a cyclic number.

It is not a de Polignac number, because 13134113 - 2⁴ = 13134097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13134091 and 13134100.

It is not a weakly prime, because it can be changed into another prime (13134193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567056 + 6567057.

It is an arithmetic number, because the mean of its divisors is an integer number (6567057).

Almost surely, 2^13134113 is an apocalyptic number.

It is an amenable number.

13134113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13134113 is an equidigital number, since it uses as much as digits as its factorization.

13134113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 108, while the sum is 17.

The square root of 13134113 is about 3624.1016817965. The cubic root of 13134113 is about 235.9392798398.

Adding to 13134113 its reverse (31143131), we get a palindrome (44277244).

The spelling of 13134113 in words is "thirteen million, one hundred thirty-four thousand, one hundred thirteen".