Base | Representation |
---|---|
bin | 10011000111001101011… |
… | …111100111101001001110 |
3 | 11122120010222121100000202 |
4 | 103013031133213221032 |
5 | 133004332114042111 |
6 | 2443212355053502 |
7 | 163614406160123 |
oct | 23071537475116 |
9 | 4576128540022 |
10 | 1313412643406 |
11 | 467019218756 |
12 | 19266b2a1292 |
13 | 96b14b16526 |
14 | 477d8a4a74a |
15 | 242716d6b3b |
hex | 131cd7e7a4e |
1313412643406 has 4 divisors (see below), whose sum is σ = 1970118965112. Its totient is φ = 656706321702.
The previous prime is 1313412643357. The next prime is 1313412643441. The reversal of 1313412643406 is 6043462143131.
It is a semiprime because it is the product of two primes.
It is a self number, because there is not a number n which added to its sum of digits gives 1313412643406.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 328353160850 + ... + 328353160853.
It is an arithmetic number, because the mean of its divisors is an integer number (492529741278).
Almost surely, 21313412643406 is an apocalyptic number.
1313412643406 is a deficient number, since it is larger than the sum of its proper divisors (656706321706).
1313412643406 is an equidigital number, since it uses as much as digits as its factorization.
1313412643406 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 656706321705.
The product of its (nonzero) digits is 124416, while the sum is 38.
Adding to 1313412643406 its reverse (6043462143131), we get a palindrome (7356874786537).
The spelling of 1313412643406 in words is "one trillion, three hundred thirteen billion, four hundred twelve million, six hundred forty-three thousand, four hundred six".
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