Base | Representation |
---|---|
bin | 10011000111001101011… |
… | …111101001010001110111 |
3 | 11122120010222121200012210 |
4 | 103013031133221101313 |
5 | 133004332114300403 |
6 | 2443212355144503 |
7 | 163614406215501 |
oct | 23071537512167 |
9 | 4576128550183 |
10 | 1313412650103 |
11 | 467019222794 |
12 | 19266b2a5133 |
13 | 96b14b195a8 |
14 | 477d8a4cd71 |
15 | 242716d8b03 |
hex | 131cd7e9477 |
1313412650103 has 16 divisors (see below), whose sum is σ = 1793507262176. Its totient is φ = 854710548480.
The previous prime is 1313412649973. The next prime is 1313412650119. The reversal of 1313412650103 is 3010562143131.
It is not a de Polignac number, because 1313412650103 - 213 = 1313412641911 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1313412652103) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30892768 + ... + 30935253.
It is an arithmetic number, because the mean of its divisors is an integer number (112094203886).
Almost surely, 21313412650103 is an apocalyptic number.
1313412650103 is a deficient number, since it is larger than the sum of its proper divisors (480094612073).
1313412650103 is an equidigital number, since it uses as much as digits as its factorization.
1313412650103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61828194.
The product of its (nonzero) digits is 6480, while the sum is 30.
Adding to 1313412650103 its reverse (3010562143131), we get a palindrome (4323974793234).
The spelling of 1313412650103 in words is "one trillion, three hundred thirteen billion, four hundred twelve million, six hundred fifty thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •