1313413540330 has 8 divisors (see below), whose sum is σ = 2364144372612. Its totient is φ = 525365416128.

The previous prime is 1313413540277. The next prime is 1313413540339. The reversal of 1313413540330 is 330453143131.

It can be written as a sum of positive squares in 2 ways, for example, as 1165918369729 + 147495170601 = 1079777^2 + 384051^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 1313413540292 and 1313413540301.

It is not an unprimeable number, because it can be changed into a prime (1313413540339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65670677007 + ... + 65670677026.

Almost surely, 2^{1313413540330} is an apocalyptic number.

1313413540330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1313413540330 is a deficient number, since it is larger than the sum of its proper divisors (1050730832282).

1313413540330 is a wasteful number, since it uses less digits than its factorization.

1313413540330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 131341354040.

The product of its (nonzero) digits is 19440, while the sum is 31.

Adding to 1313413540330 its reverse (330453143131), we get a palindrome (1643866683461).

The spelling of 1313413540330 in words is "one trillion, three hundred thirteen billion, four hundred thirteen million, five hundred forty thousand, three hundred thirty".