Base | Representation |
---|---|
bin | 10011000111001101111… |
… | …011101100111101011011 |
3 | 11122120011111110100112012 |
4 | 103013031323230331123 |
5 | 133004341010131321 |
6 | 2443213220540135 |
7 | 163614525561116 |
oct | 23071573547533 |
9 | 4576144410465 |
10 | 1313420005211 |
11 | 467022396796 |
12 | 19267185164b |
13 | 96b164c3322 |
14 | 477d9a0557d |
15 | 2427218d05b |
hex | 131cdeecf5b |
1313420005211 has 2 divisors, whose sum is σ = 1313420005212. Its totient is φ = 1313420005210.
The previous prime is 1313420005207. The next prime is 1313420005229. The reversal of 1313420005211 is 1125000243131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1313420005211 - 22 = 1313420005207 is a prime.
It is a super-2 number, since 2×13134200052112 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1313420005201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656710002605 + 656710002606.
It is an arithmetic number, because the mean of its divisors is an integer number (656710002606).
Almost surely, 21313420005211 is an apocalyptic number.
1313420005211 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313420005211 is an equidigital number, since it uses as much as digits as its factorization.
1313420005211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 1313420005211 its reverse (1125000243131), we get a palindrome (2438420248342).
The spelling of 1313420005211 in words is "one trillion, three hundred thirteen billion, four hundred twenty million, five thousand, two hundred eleven".
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