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131342020403 = 1122761139313
BaseRepresentation
bin111101001010010011…
…0000010111100110011
3110120000110011221112012
41322110212002330303
54122442024123103
6140200535153135
712326530516166
oct1722446027463
9416013157465
10131342020403
115077a167a00
12215562157ab
13c501c32b49
1464dd807add
15363aaa42d8
hex1e94982f33

131342020403 has 12 divisors (see below), whose sum is σ = 144376576344. Its totient is φ = 119394475200.

The previous prime is 131342020391. The next prime is 131342020429. The reversal of 131342020403 is 304020243131.

It is not a de Polignac number, because 131342020403 - 222 = 131337826099 is a prime.

It is not an unprimeable number, because it can be changed into a prime (131342020463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3321275 + ... + 3360587.

It is an arithmetic number, because the mean of its divisors is an integer number (12031381362).

Almost surely, 2131342020403 is an apocalyptic number.

131342020403 is a deficient number, since it is larger than the sum of its proper divisors (13034555941).

131342020403 is a wasteful number, since it uses less digits than its factorization.

131342020403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66946 (or 66935 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 131342020403 its reverse (304020243131), we get a palindrome (435362263534).

The spelling of 131342020403 in words is "one hundred thirty-one billion, three hundred forty-two million, twenty thousand, four hundred three".

Divisors: 1 11 121 27611 39313 303721 432443 3340931 4756873 1085471243 11940183673 131342020403