13134231312403 has 2 divisors, whose sum is σ = 13134231312404. Its totient is φ = 13134231312402.

The previous prime is 13134231312401. The next prime is 13134231312463. The reversal of 13134231312403 is 30421313243131.

It is a weak prime.

It is an emirp because it is prime and its reverse (30421313243131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13134231312403 - 2¹ = 13134231312401 is a prime.

Together with 13134231312401, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13134231312401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567115656201 + 6567115656202.

It is an arithmetic number, because the mean of its divisors is an integer number (6567115656202).

Almost surely, 2^{13134231312403} is an apocalyptic number.

13134231312403 is a deficient number, since it is larger than the sum of its proper divisors (1).

13134231312403 is an equidigital number, since it uses as much as digits as its factorization.

13134231312403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 13134231312403 its reverse (30421313243131), we get a palindrome (43555544555534).

The spelling of 13134231312403 in words is "thirteen trillion, one hundred thirty-four billion, two hundred thirty-one million, three hundred twelve thousand, four hundred three".