Base | Representation |
---|---|
bin | 11101110111010010001011… |
… | …011111011111011101101111 |
3 | 122020001012210111002021122222 |
4 | 131313102023133133131233 |
5 | 114203403304142400142 |
6 | 1143201514542225555 |
7 | 36444115052140616 |
oct | 3567221337373557 |
9 | 566035714067588 |
10 | 131342440200047 |
11 | 3893901a44790a |
12 | 128930655852bb |
13 | 583970115441b |
14 | 246101803a87d |
15 | 102b7b931cbd2 |
hex | 77748b7df76f |
131342440200047 has 2 divisors, whose sum is σ = 131342440200048. Its totient is φ = 131342440200046.
The previous prime is 131342440200019. The next prime is 131342440200239. The reversal of 131342440200047 is 740002044243131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131342440200047 - 210 = 131342440199023 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131342440200007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65671220100023 + 65671220100024.
It is an arithmetic number, because the mean of its divisors is an integer number (65671220100024).
Almost surely, 2131342440200047 is an apocalyptic number.
131342440200047 is a deficient number, since it is larger than the sum of its proper divisors (1).
131342440200047 is an equidigital number, since it uses as much as digits as its factorization.
131342440200047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64512, while the sum is 35.
Adding to 131342440200047 its reverse (740002044243131), we get a palindrome (871344484443178).
The spelling of 131342440200047 in words is "one hundred thirty-one trillion, three hundred forty-two billion, four hundred forty million, two hundred thousand, forty-seven".
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