Base | Representation |
---|---|
bin | 1011111100100000111010… |
… | …0000010011111011000100 |
3 | 1201111121210200211221210110 |
4 | 2333020032200103323010 |
5 | 3210142422323424104 |
6 | 43533443115353020 |
7 | 2523630020235045 |
oct | 277101640237304 |
9 | 51447720757713 |
10 | 13134253342404 |
11 | 4204229669a37 |
12 | 158160aa52770 |
13 | 743729ac44ac |
14 | 3359b63508cc |
15 | 17b9bab14e89 |
hex | bf20e813ec4 |
13134253342404 has 48 divisors (see below), whose sum is σ = 32503298405760. Its totient is φ = 4119081584640.
The previous prime is 13134253342393. The next prime is 13134253342409. The reversal of 13134253342404 is 40424335243131.
It is a super-4 number, since 4×131342533424044 (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (13134253342409) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 390047709 + ... + 390081380.
It is an arithmetic number, because the mean of its divisors is an integer number (677152050120).
Almost surely, 213134253342404 is an apocalyptic number.
It is an amenable number.
13134253342404 is an abundant number, since it is smaller than the sum of its proper divisors (19369045063356).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13134253342404 is a wasteful number, since it uses less digits than its factorization.
13134253342404 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 780129180 (or 780129178 counting only the distinct ones).
The product of its (nonzero) digits is 414720, while the sum is 39.
Adding to 13134253342404 its reverse (40424335243131), we get a palindrome (53558588585535).
The spelling of 13134253342404 in words is "thirteen trillion, one hundred thirty-four billion, two hundred fifty-three million, three hundred forty-two thousand, four hundred four".
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