Base | Representation |
---|---|
bin | 11000011101101110… |
… | …11101001000010011 |
3 | 1020220100112121001202 |
4 | 30032313131020103 |
5 | 203344341221042 |
6 | 10011150021415 |
7 | 643323610364 |
oct | 141667351023 |
9 | 36810477052 |
10 | 13134320147 |
11 | 562aa88143 |
12 | 26667a786b |
13 | 1314170990 |
14 | 8c8531b6b |
15 | 51d135632 |
hex | 30eddd213 |
13134320147 has 4 divisors (see below), whose sum is σ = 14144652480. Its totient is φ = 12123987816.
The previous prime is 13134320137. The next prime is 13134320149. The reversal of 13134320147 is 74102343131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13134320147 - 224 = 13117542931 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13134320149) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 505166147 + ... + 505166172.
It is an arithmetic number, because the mean of its divisors is an integer number (3536163120).
Almost surely, 213134320147 is an apocalyptic number.
13134320147 is a deficient number, since it is larger than the sum of its proper divisors (1010332333).
13134320147 is a wasteful number, since it uses less digits than its factorization.
13134320147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1010332332.
The product of its (nonzero) digits is 6048, while the sum is 29.
Adding to 13134320147 its reverse (74102343131), we get a palindrome (87236663278).
The spelling of 13134320147 in words is "thirteen billion, one hundred thirty-four million, three hundred twenty thousand, one hundred forty-seven".
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