Base | Representation |
---|---|
bin | 1011111100100001001001… |
… | …1111101110111111010011 |
3 | 1201111121222100211202022221 |
4 | 2333020102133232333103 |
5 | 3210143041444044422 |
6 | 43533453510441511 |
7 | 2523631462330465 |
oct | 277102237567723 |
9 | 51447870752287 |
10 | 13134320299987 |
11 | 4204263442187 |
12 | 1581629363297 |
13 | 74373a939273 |
14 | 3359c11c0135 |
15 | 17b9c193e3c7 |
hex | bf2127eefd3 |
13134320299987 has 2 divisors, whose sum is σ = 13134320299988. Its totient is φ = 13134320299986.
The previous prime is 13134320299967. The next prime is 13134320300033. The reversal of 13134320299987 is 78999202343131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13134320299987 - 215 = 13134320267219 is a prime.
It is not a weakly prime, because it can be changed into another prime (13134320299967) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567160149993 + 6567160149994.
It is an arithmetic number, because the mean of its divisors is an integer number (6567160149994).
Almost surely, 213134320299987 is an apocalyptic number.
13134320299987 is a deficient number, since it is larger than the sum of its proper divisors (1).
13134320299987 is an equidigital number, since it uses as much as digits as its factorization.
13134320299987 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17635968, while the sum is 61.
The spelling of 13134320299987 in words is "thirteen trillion, one hundred thirty-four billion, three hundred twenty million, two hundred ninety-nine thousand, nine hundred eighty-seven".
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