131343203012433 has 4 divisors (see below), whose sum is σ = 175124270683248. Its totient is φ = 87562135341620.

The previous prime is 131343203012423. The next prime is 131343203012453. The reversal of 131343203012433 is 334210302343131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131343203012433 - 2⁹ = 131343203011921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131343203012394 and 131343203012403.

It is not an unprimeable number, because it can be changed into a prime (131343203012423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21890533835403 + ... + 21890533835408.

It is an arithmetic number, because the mean of its divisors is an integer number (43781067670812).

Almost surely, 2^{131343203012433} is an apocalyptic number.

It is an amenable number.

131343203012433 is a deficient number, since it is larger than the sum of its proper divisors (43781067670815).

131343203012433 is an equidigital number, since it uses as much as digits as its factorization.

131343203012433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43781067670814.

The product of its (nonzero) digits is 46656, while the sum is 33.

Adding to 131343203012433 its reverse (334210302343131), we get a palindrome (465553505355564).

The spelling of 131343203012433 in words is "one hundred thirty-one trillion, three hundred forty-three billion, two hundred three million, twelve thousand, four hundred thirty-three".