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131343203013079 is a prime number
BaseRepresentation
bin11101110111010010111000…
…111101011001000111010111
3122020001021202122110012102111
4131313102320331121013113
5114203411334432404304
61143202122352051451
736444143004013411
oct3567227075310727
9566037678405374
10131343203013079
1138939380a99602
1212893238b33b87
1358397c31b6c95
14246108b4859b1
15102b81129b704
hex7774b8f591d7

131343203013079 has 2 divisors, whose sum is σ = 131343203013080. Its totient is φ = 131343203013078.

The previous prime is 131343203012947. The next prime is 131343203013131. The reversal of 131343203013079 is 970310302343131.

It is a strong prime.

It is an emirp because it is prime and its reverse (970310302343131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131343203013079 - 243 = 122547109990871 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131343203013779) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65671601506539 + 65671601506540.

It is an arithmetic number, because the mean of its divisors is an integer number (65671601506540).

Almost surely, 2131343203013079 is an apocalyptic number.

131343203013079 is a deficient number, since it is larger than the sum of its proper divisors (1).

131343203013079 is an equidigital number, since it uses as much as digits as its factorization.

131343203013079 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 122472, while the sum is 40.

The spelling of 131343203013079 in words is "one hundred thirty-one trillion, three hundred forty-three billion, two hundred three million, thirteen thousand, seventy-nine".