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131343232420447 is a prime number
BaseRepresentation
bin11101110111010010111010…
…101101100100101001011111
3122020001021211200210020202021
4131313102322231210221133
5114203411414444423242
61143202125322241011
736444143511663235
oct3567227255445137
9566037750706667
10131343232420447
1138939396654813
1212893246956167
1358397c93122a8
14246109133c955
15102b813b59b67
hex7774bab64a5f

131343232420447 has 2 divisors, whose sum is σ = 131343232420448. Its totient is φ = 131343232420446.

The previous prime is 131343232420297. The next prime is 131343232420501. The reversal of 131343232420447 is 744024232343131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131343232420447 - 231 = 131341084936799 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131343232400447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65671616210223 + 65671616210224.

It is an arithmetic number, because the mean of its divisors is an integer number (65671616210224).

Almost surely, 2131343232420447 is an apocalyptic number.

131343232420447 is a deficient number, since it is larger than the sum of its proper divisors (1).

131343232420447 is an equidigital number, since it uses as much as digits as its factorization.

131343232420447 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1161216, while the sum is 43.

Adding to 131343232420447 its reverse (744024232343131), we get a palindrome (875367464763578).

The spelling of 131343232420447 in words is "one hundred thirty-one trillion, three hundred forty-three billion, two hundred thirty-two million, four hundred twenty thousand, four hundred forty-seven".