Base | Representation |
---|---|
bin | 1011111100100001001010… |
… | …1011101011111111001111 |
3 | 1201111121222120201221121010 |
4 | 2333020102223223333033 |
5 | 3210143043244332143 |
6 | 43533454101540303 |
7 | 2523631531061043 |
oct | 277102253537717 |
9 | 51447876657533 |
10 | 13134323433423 |
11 | 42042651923a5 |
12 | 158162a414693 |
13 | 74373b49557a |
14 | 3359c1798023 |
15 | 17b9c1d5ca33 |
hex | bf212aebfcf |
13134323433423 has 4 divisors (see below), whose sum is σ = 17512431244568. Its totient is φ = 8756215622280.
The previous prime is 13134323433401. The next prime is 13134323433443. The reversal of 13134323433423 is 32433432343131.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13134323433423 - 25 = 13134323433391 is a prime.
It is a super-2 number, since 2×131343234334232 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13134323433443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2189053905568 + ... + 2189053905573.
It is an arithmetic number, because the mean of its divisors is an integer number (4378107811142).
Almost surely, 213134323433423 is an apocalyptic number.
13134323433423 is a deficient number, since it is larger than the sum of its proper divisors (4378107811145).
13134323433423 is an equidigital number, since it uses as much as digits as its factorization.
13134323433423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4378107811144.
The product of its digits is 559872, while the sum is 39.
Adding to 13134323433423 its reverse (32433432343131), we get a palindrome (45567755776554).
The spelling of 13134323433423 in words is "thirteen trillion, one hundred thirty-four billion, three hundred twenty-three million, four hundred thirty-three thousand, four hundred twenty-three".
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