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13134323434097 is a prime number
BaseRepresentation
bin1011111100100001001010…
…1011101100001001110001
31201111121222120201222112002
42333020102223230021301
53210143043244342342
643533454101543345
72523631531063025
oct277102253541161
951447876658462
1013134323434097
114204265192958
12158162a414b55
1374373b495978
143359c1798385
1517b9c1d5cd32
hexbf212aec271

13134323434097 has 2 divisors, whose sum is σ = 13134323434098. Its totient is φ = 13134323434096.

The previous prime is 13134323433997. The next prime is 13134323434121. The reversal of 13134323434097 is 79043432343131.

13134323434097 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11571045837376 + 1563277596721 = 3401624^2 + 1250311^2 .

It is a cyclic number.

It is not a de Polignac number, because 13134323434097 - 224 = 13134306656881 is a prime.

It is a super-2 number, since 2×131343234340972 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13134323634097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567161717048 + 6567161717049.

It is an arithmetic number, because the mean of its divisors is an integer number (6567161717049).

Almost surely, 213134323434097 is an apocalyptic number.

It is an amenable number.

13134323434097 is a deficient number, since it is larger than the sum of its proper divisors (1).

13134323434097 is an equidigital number, since it uses as much as digits as its factorization.

13134323434097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1959552, while the sum is 47.

The spelling of 13134323434097 in words is "thirteen trillion, one hundred thirty-four billion, three hundred twenty-three million, four hundred thirty-four thousand, ninety-seven".