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13134323434121 is a prime number
BaseRepresentation
bin1011111100100001001010…
…1011101100001010001001
31201111121222120201222112222
42333020102223230022021
53210143043244342441
643533454101543425
72523631531063061
oct277102253541211
951447876658488
1013134323434121
11420426519297a
12158162a414b75
1374373b495996
143359c17983a1
1517b9c1d5cd4b
hexbf212aec289

13134323434121 has 2 divisors, whose sum is σ = 13134323434122. Its totient is φ = 13134323434120.

The previous prime is 13134323434097. The next prime is 13134323434147. The reversal of 13134323434121 is 12143432343131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12036042490000 + 1098280944121 = 3469300^2 + 1047989^2 .

It is a cyclic number.

It is not a de Polignac number, because 13134323434121 - 222 = 13134319239817 is a prime.

It is not a weakly prime, because it can be changed into another prime (13134323434621) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567161717060 + 6567161717061.

It is an arithmetic number, because the mean of its divisors is an integer number (6567161717061).

Almost surely, 213134323434121 is an apocalyptic number.

It is an amenable number.

13134323434121 is a deficient number, since it is larger than the sum of its proper divisors (1).

13134323434121 is an equidigital number, since it uses as much as digits as its factorization.

13134323434121 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 62208, while the sum is 35.

Adding to 13134323434121 its reverse (12143432343131), we get a palindrome (25277755777252).

The spelling of 13134323434121 in words is "thirteen trillion, one hundred thirty-four billion, three hundred twenty-three million, four hundred thirty-four thousand, one hundred twenty-one".