Search a number
-
+
131343304222139 is a prime number
BaseRepresentation
bin11101110111010010111110…
…111111011110010110111011
3122020001022000200220011011012
4131313102332333132112323
5114203412041340102024
61143202140405224135
736444145343202512
oct3567227677362673
9566038020804135
10131343304222139
1138939423136459
1212893266a0204b
13583980b161bb9
14246109aaad679
15102b81a0de50e
hex7774befde5bb

131343304222139 has 2 divisors, whose sum is σ = 131343304222140. Its totient is φ = 131343304222138.

The previous prime is 131343304222111. The next prime is 131343304222199. The reversal of 131343304222139 is 931222403343131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131343304222139 - 224 = 131343287444923 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131343304222096 and 131343304222105.

It is not a weakly prime, because it can be changed into another prime (131343304222199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65671652111069 + 65671652111070.

It is an arithmetic number, because the mean of its divisors is an integer number (65671652111070).

Almost surely, 2131343304222139 is an apocalyptic number.

131343304222139 is a deficient number, since it is larger than the sum of its proper divisors (1).

131343304222139 is an equidigital number, since it uses as much as digits as its factorization.

131343304222139 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 279936, while the sum is 41.

The spelling of 131343304222139 in words is "one hundred thirty-one trillion, three hundred forty-three billion, three hundred four million, two hundred twenty-two thousand, one hundred thirty-nine".