Base | Representation |
---|---|
bin | 11101110111010010111110… |
… | …111111011110010110011111 |
3 | 122020001022000200220011010011 |
4 | 131313102332333132112133 |
5 | 114203412041340101421 |
6 | 1143202140405224051 |
7 | 36444145343202442 |
oct | 3567227677362637 |
9 | 566038020804104 |
10 | 131343304222111 |
11 | 38939423136433 |
12 | 12893266a02027 |
13 | 583980b161b97 |
14 | 246109aaad659 |
15 | 102b81a0de4e1 |
hex | 7774befde59f |
131343304222111 has 2 divisors, whose sum is σ = 131343304222112. Its totient is φ = 131343304222110.
The previous prime is 131343304222103. The next prime is 131343304222139. The reversal of 131343304222111 is 111222403343131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131343304222111 - 23 = 131343304222103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131343304262111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65671652111055 + 65671652111056.
It is an arithmetic number, because the mean of its divisors is an integer number (65671652111056).
Almost surely, 2131343304222111 is an apocalyptic number.
131343304222111 is a deficient number, since it is larger than the sum of its proper divisors (1).
131343304222111 is an equidigital number, since it uses as much as digits as its factorization.
131343304222111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 131343304222111 its reverse (111222403343131), we get a palindrome (242565707565242).
The spelling of 131343304222111 in words is "one hundred thirty-one trillion, three hundred forty-three billion, three hundred four million, two hundred twenty-two thousand, one hundred eleven".
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